Tag: Marcolli

Do we need the sphere spectrum?

Published December 31, 2021 by lieven

Last time I mentioned the talk “From noncommutative geometry to the tropical geometry of the scaling site” by Alain Connes, culminating in the canonical isomorphism (last slide of the talk)

Or rather, what is actually proved in his paper with Caterina Consani BC-system, absolute cyclotomy and the quantized calculus (and which they conjectured previously to be the case in Segal’s Gamma rings and universal arithmetic), is a canonical isomorphism between the $λ$ -rings
$Z [Q / Z] ≃ W_{0} (\overset{―}{S})$
The left hand side is the integral groupring of the additive quotient-group $Q / Z$ , or if you prefer, $Z [μ_{\infty}]$ the integral groupring of the multiplicative group of all roots of unity $μ_{\infty}$ .

The power maps on $μ_{\infty}$ equip $Z [μ_{\infty}]$ with a $λ$ -ring structure, that is, a family of commuting endomorphisms $σ_{n}$ with $σ_{n} (ζ) = ζ^{n}$ for all $ζ \in μ_{\infty}$ , and a family of linear maps $ρ_{n}$ induced by requiring for all $ζ \in μ_{\infty}$ that
$ρ_{n} (ζ) = \sum_{μ^{n} = ζ} μ$
The maps $σ_{n}$ and $ρ_{n}$ are used to construct an integral version of the Bost-Connes algebra describing the Bost-Connes sytem, a quantum statistical dynamical system.

On the right hand side, $S$ is the sphere spectrum (an object from stable homotopy theory) and $\overset{―}{S}$ its ‘algebraic closure’, that is, adding all abstract roots of unity.

The ring $W_{0} (\overset{―}{S})$ is a generalisation to the world of spectra of the Almkvist-ring $W_{0} (R)$ defined for any commutative ring $R$ , constructed from pairs $(E, f)$ where $E$ is a projective $R$ -module of finite rank and $f$ an $R$ -endomorphism on it. Addition and multiplication are coming from direct sums and tensor products of such pairs, with zero element the pair $(0, 0)$ and unit element the pair $(R, 1_{R})$ . The ring $W_{0} (R)$ is then the quotient-ring obtained by dividing out the ideal consisting of all zero-pairs $(E, 0)$ .

The ring $W_{0} (R)$ becomes a $λ$ -ring via the Frobenius endomorphisms $F_{n}$ sending a pair $(E, f)$ to the pair $(E, f^{n})$ , and we also have a collection of linear maps on $W_{0} (R)$ , the ‘Verschiebung’-maps which send a pair $(E, f)$ to the pair $(E^{\oplus n}, F)$ with
$F = [\begin{matrix} 0 & 0 & 0 & \dots & f \\ 1 & 0 & 0 & \dots & 0 \\ 0 & 1 & 0 & \dots & 0 \\ ⋮ & ⋮ & ⋮ & ⋮ \\ 0 & 0 & 0 & \dots & 1 \end{matrix}]$
Connes and Consani define a notion of modules and their endomorphisms for $S$ and $\overset{―}{S}$ , allowing them to define in a similar way the rings $W_{0} (S)$ and $W_{0} (\overset{―}{S})$ , with corresponding maps $F_{n}$ and $V_{n}$ . They then establish an isomorphism with $Z [Q / Z]$ such that the maps $(F_{n}, V_{n})$ correspond to $(σ_{n}, ρ_{n})$ .

But, do we really have the go to spectra to achieve this?

All this reminds me of an old idea of Yuri Manin mentioned in the introduction of his paper Cyclotomy and analytic geometry over $F_{1}$ , and later elaborated in section two of his paper with Matilde Marcolli Homotopy types and geometries below $Spec (Z)$ .

Take a manifold $M$ with a diffeomorphism $f$ and consider the corresponding discrete dynamical system by iterating the diffeomorphism. In such situations it is important to investigate the periodic orbits, or the fix-points $F i x (M, f^{n})$ for all $n$ . If we are in a situation that the number of fixed points is finite we can package these numbers in the Artin-Mazur zeta function
$ζ_{A M} (M, f) = e x p (\sum_{n = 1}^{\infty} \frac{# F i x (M, f^{n})}{n} t^{n})$
and investigate the properties of this function.

To connect this type of problem to Almkvist-like rings, Manin considers the Morse-Smale dynamical systems, a structural stable diffeomorphism $f$ , having a finite number of non-wandering points on a compact manifold $M$ .

From Topological classification of Morse-Smale diffeomorphisms on 3-manifolds

In such a situation $f_{*}$ acts on homology $H_{k} (M, Z)$ , which are free $Z$ -modules of finite rank, as a matrix $M_{f}$ having only roots of unity as its eigenvalues.

Manin argues that this action is similar to the action of the Frobenius on etale cohomology groups, in which case the eigenvalues are Weil numbers. That is, one might view roots of unity as Weil numbers in characteristic one.

Clearly, all relevant data $(H_{k} (M, Z), f_{*})$ belongs to the $λ$ -subring of $W_{0} (Z)$ generated by all pairs $(E, f)$ such that $M_{f}$ is diagonalisable and all its eigenvalues are either $0$ or roots of unity.

If we denote for any ring $R$ by $W_{1} (R)$ this $λ$ -subring of $W_{0} (R)$ , probably one would obtain canonical isomorphisms

– between $W_{1} (Z)$ and the invariant part of the integral groupring $Z [Q / Z]$ for the action of the group $A u t (Q / Z) = {\hat{Z}}^{*}$ , and

– between $Z [Q / Z]$ and $W_{1} (Z (μ_{\infty}))$ where $Z (μ_{\infty})$ is the ring obtained by adjoining to $Z$ all roots of unity.

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Complete chaos and Belyi-extenders

Published August 23, 2019 by lieven

A Belyi-extender (or dessinflateur) is a rational function $q (t) = \frac{f (t)}{g (t)} \in Q (t)$ that defines a map
$q : P_{C}^{1} \to P_{C}^{1}$
unramified outside ${0, 1, \infty}$ , and has the property that $q ({0, 1, \infty}) \subseteq {0, 1, \infty}$ .

An example of such a Belyi-extender is the power map $q (t) = t^{n}$ , which is totally ramified in $0$ and $\infty$ and we clearly have that $q (0) = 0, q (1) = 1$ and $q (\infty) = \infty$ .

The composition of two Belyi-extenders is again an extender, and we get a rather mysterious monoid $E$ of all Belyi-extenders.

Very little seems to be known about this monoid. Its units form the symmetric group $S_{3}$ which is the automrphism group of $P_{C}^{1} - {0, 1, \infty}$ , and mapping an extender $q$ to its degree gives a monoid map $E \to N_{+}^{\times}$ to the multiplicative monoid of positive natural numbers.

If one relaxes the condition of $q (t) \in Q (t)$ to being defined over its algebraic closure $\overset{―}{Q}$ , then such maps/functions have been known for some time under the name of dynamical Belyi-functions, for example in Zvonkin’s Belyi Functions: Examples, Properties, and Applications (section 6).

Here, one is interested in the complex dynamical system of iterations of $q$ , that is, the limit-behaviour of the orbits
${z, q (z), q^{2} (z), q^{3} (z), \dots}$
for all complex numbers $z \in C$ .

In general, the 2-sphere $P_{C}^{1} = S^{2}$ has a finite number of open sets (the Fatou domains) where the limit behaviour of the series is similar, and the union of these open sets is dense in $S^{2}$ . The complement of the Fatou domains is the Julia set of the function, of which we might expect a nice fractal picture.

Let’s take again the power map $q (t) = t^{n}$ . For a complex number $z$ lying outside the unit disc, the series ${z, z^{n}, z^{2 n}, \dots}$ has limit point $\infty$ and for those lying inside the unit circle, this limit is $0$ . So, here we have two Fatou domains (interior and exterior of the unit circle) and the Julia set of the power map is the (boring?) unit circle.

Fortunately, there are indeed dynamical Belyi-maps having a more pleasant looking Julia set, such as this one

But then, many dynamical Belyi-maps (and Belyi-extenders) are systems of an entirely different nature, they are completely chaotic, meaning that their Julia set is the whole $2$ -sphere! Nowhere do we find an open region where points share the same limit behaviour… (the butterfly effect).

There’s a nice sufficient condition for chaotic behaviour, due to Dennis Sullivan, which is pretty easy to check for dynamical Belyi-maps.

A periodic point for $q (t)$ is a point $p \in S^{2} = P_{C}^{1}$ such that $p = q^{m} (p)$ for some $m > 1$ . A critical point is one such that either $q (p) = \infty$ or $q^{'} (p) = 0$ .

Sullivan’s result is that $q (t)$ is completely chaotic when all its critical points $p$ become eventually periodic, that is some $q^{k} (p)$ is periodic, but $p$ itself is not periodic.

For a Belyi-map $q (t)$ the critical points are either comlex numbers mapping to $\infty$ or the inverse images of $0$ or $1$ (that is, the black or white dots in the dessin of $q (t)$ ) which are not leaf-vertices of the dessin.

Let’s do an example, already used by Sullivan himself:
$q (t) = (\frac{t - 2}{t})^{2}$
This is a Belyi-function, and in fact a Belyi-extender as it is defined over $Q$ and we have that $q (0) = \infty$ , $q (1) = 1$ and $q (\infty) = 1$ . The corresponding dessin is (inverse images of $\infty$ are marked with an $*$ )

The critical points $0$ and $2$ are not periodic, but they become eventually periodic:

$2 \to^{q} 0 \to^{q} \infty \to^{q} 1 \to^{q} 1$
and $1$ is periodic.

For a general Belyi-extender $q$ , we have that the image under $q$ of any critical point is among ${0, 1, \infty}$ and because we demand that $q ({0, 1, \infty}) \subseteq {0, 1, \infty}$ , every critical point of $q$ eventually becomes periodic.

If we want to avoid the corresponding dynamical system to be completely chaotic, we have to ensure that one of the periodic points among ${0, 1, \infty}$ (and there is at least one of those) must be critical.

Let’s consider the very special Belyi-extenders $q$ having the additional property that $q (0) = 0$ , $q (1) = 1$ and $q (\infty) = \infty$ , then all three of them are periodic.

So, the system is always completely chaotic unless the black dot at $0$ is not a leaf-vertex of the dessin, or the white dot at $1$ is not a leaf-vertex, or the degree of the region determined by the starred $\infty$ is at least two.

Going back to the mystery Manin-Marcolli sub-monoid of $E$ , it might explain why it is a good idea to restrict to very special Belyi-extenders having associated dessin a $2$ -coloured tree, for then the periodic point $\infty$ is critical (the degree of the outside region is at least two), and therefore the conditions of Sullivan’s theorem are not satisfied. So, these Belyi-extenders do not necessarily have to be completely chaotic. (tbc)

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the mystery Manin-Marcolli monoid

Published August 14, 2019 by lieven

A Belyi-extender (or dessinflateur) $β$ of degree $d$ is a quotient of two polynomials with rational coefficients
$β (t) = \frac{f (t)}{g (t)}$
with the special properties that for each complex number $c$ the polynomial equation of degree $d$ in $t$
$f (t) - c g (t) = 0$
has $d$ distinct solutions, except perhaps for $c = 0$ or $c = 1$ , and, in addition, we have that
$β (0), β (1), β (\infty) \in {0, 1, \infty}$

Let’s take for instance the power maps $β_{n} (t) = t^{n}$ .

For every $c$ the degree $n$ polynomial $t^{n} - c = 0$ has exactly $n$ distinct solutions, except for $c = 0$ , when there is just one. And, clearly we have that $0^{n} = 0$ , $1^{n} = 1$ and $\infty^{n} = \infty$ . So, $β_{n}$ is a Belyi-extender of degree $n$ .

A cute observation being that if $β$ is a Belyi-extender of degree $d$ , and $β^{'}$ is an extender of degree $d^{'}$ , then $β \circ β^{'}$ is again a Belyi-extender, this time of degree $d . d^{'}$ .

That is, Belyi-extenders form a monoid under composition!

In our example, $β_{n} \circ β_{m} = β_{n . m}$ . So, the power-maps are a sub-monoid of the Belyi-extenders, isomorphic to the multiplicative monoid $N_{\times}$ of strictly positive natural numbers.

In their paper Quantum statistical mechanics of the absolute Galois group, Yuri I. Manin and Matilde Marcolli say they use the full monoid of Belyi-extenders to act on all Grothendieck’s dessins d’enfant.

But, they attach properties to these Belyi-extenders which they don’t have, in general. That’s fine, as they foresee in Remark 2.21 of their paper that the construction works equally well for any suitable sub-monoid, as long as this sub-monoid contains all power-map exenders.

I’m trying to figure out what the maximal mystery sub-monoid of extenders is satisfying all the properties they need for their proofs.

But first, let us see what Belyi-extenders have to do with dessins d’enfant.

In his user-friendlier period, Grothendieck told us how to draw a picture, which he called a dessin d’enfant, of an extender $β (t) = \frac{f (t)}{g (t)}$ of degree $d$ :

Look at all complex solutions of $f (t) = 0$ and label them with a black dot (and add a black dot at $\infty$ if $β (\infty) = 0$ ). Now, look at all complex solutions of $f (t) - g (t) = 0$ and label them with a white dot (and add a white dot at $\infty$ if $β (\infty) = 1$ ).

Now comes the fun part.

Because $β$ has exactly $d$ pre-images for all real numbers $λ$ in the open interval $(0, 1)$ (and $β$ is continuous), we can connect the black dots with the white dots by $d$ edges (the pre-images of the open interval $(0, 1)$ ), giving us a $2$ -coloured graph.

For the power-maps $β_{n} (t) = t^{n}$ , we have just one black dot at $0$ (being the only solution of $t^{n} = 0$ ), and $n$ white dots at the $n$ -th roots of unity (the solutions of $x^{n} - 1 = 0$ ). Any $λ \in (0, 1)$ has as its $n$ pre-images the numbers $ζ_{i} . \sqrt[n]{λ}$ with $ζ_{i}$ an $n$ -th root of unity, so we get here as picture an $n$ -star. Here for $n = 5$ :

This dessin should be viewed on the 2-sphere, with the antipodal point of $0$ being $\infty$ , so projecting from $\infty$ gives a homeomorphism between the 2-sphere and $C \cup {\infty}$ .

To get all information of the dessin (including possible dots at infinity) it is best to slice the sphere open along the real segments $(\infty, 0)$ and $(1, \infty)$ and flatten it to form a ‘diamond’ with the upper triangle corresponding to the closed upper semisphere and the lower triangle to the open lower semisphere.

In the picture above, the right hand side is the dessin drawn in the diamond, and this representation will be important when we come to the action of extenders on more general Grothendieck dessins d’enfant.

Okay, let’s try to get some information about the monoid $E$ of all Belyi-extenders.

What are its invertible elements?

Well, we’ve seen that the degree of a composition of two extenders is the product of their degrees, so invertible elements must have degree $1$ , so are automorphisms of $P_{C}^{1} - {0, 1, \infty} = S^{2} - {0, 1, \infty}$ permuting the set ${0, 1, \infty}$ .

They form the symmetric group $S_{3}$ on $3$ -letters and correspond to the Belyi-extenders
$t, 1 - t, \frac{1}{t}, \frac{1}{1 - t}, \frac{t - 1}{t}, \frac{t}{t - 1}$
You can compose these units with an extender to get anther extender of the same degree where the roles of $0, 1$ and $\infty$ are changed.

For example, if you want to colour all your white dots black and the black dots white, you compose with the unit $1 - t$ .

Manin and Marcolli use this and claim that you can transform any extender $η$ to an extender $γ$ by composing with a unit, such that $γ (0) = 0, γ (1) = 1$ and $γ (\infty) = \infty$ .

That’s fine as long as your original extender $η$ maps ${0, 1, \infty}$ onto ${0, 1, \infty}$ , but usually a Belyi-extender only maps into ${0, 1, \infty}$ .

Here are some extenders of degree three (taken from Melanie Wood’s paper Belyi-extending maps and the Galois action on dessins d’enfants):

with dessin $5$ corresponding to the Belyi-extender
$β (t) = \frac{t^{2} (t - 1)}{(t - \frac{4}{3})^{3}}$
with $β (0) = 0 = β (1)$ and $β (\infty) = 1$ .

So, a first property of the mystery Manin-Marcolli monoid $E_{M M M}$ must surely be that all its elements $γ (t)$ map ${0, 1, \infty}$ onto ${0, 1, \infty}$ , for they use this property a number of times, for instance to construct a monoid map
$E_{M M M} \to M_{2} (Z)^{+} γ \mapsto [\begin{matrix} d & m - 1 \\ 0 & 1 \end{matrix}]$
where $d$ is the degree of $γ$ and $m$ is the number of black dots in the dessin (or white dots for that matter).

Further, they seem to believe that the dessin of any Belyi-extender must be a 2-coloured tree.

Already last time we’ve encountered a Belyi-extender $ζ (t) = \frac{27 t^{2} (t - 1)^{2}}{4 (t^{2} - t + 1)^{3}}$ with dessin

But then, you may argue, this extender sends all of $0, 1$ and $\infty$ to $0$ , so it cannot belong to $E_{M M M}$ .

Here’s a trick to construct Belyi-extenders from Belyi-maps $β : P^{1} \to P^{1}$ , defined over $Q$ and having the property that there are rational points in the fibers over $0, 1$ and $\infty$ .

Let’s take an example, the ‘monstrous dessin’ corresponding to the congruence subgroup $Γ_{0} (2)$

with map $β (t) = \frac{(t + 256)^{3}}{1728 t^{2}}$ .

As it stands, $β$ is not a Belyi-extender because it does not map $1$ into ${0, 1, \infty}$ . But we have that
$- 256 \in β^{- 1} (0), \infty \in β^{- 1} (\infty), and 512, - 64 \in β^{- 1} (1)$
(the last one follows from $(t + 256)^{2} - 1728 t^{3} = (t - 512)^{2} (t + 64)$ ).

We can now pre-compose $β$ with the automorphism (defined over $Q$ ) sending $0$ to $- 256$ , $1$ to $- 64$ and fixing $\infty$ to get a Belyi-extender
$γ (t) = \frac{(192 t)^{3}}{1728 (192 t - 256)^{2}}$
which maps $γ (0) = 0, γ (1) = 1$ and $γ (\infty) = \infty$ (so belongs to $E_{M M M}$ ) with the same dessin, which is not a tree,

That is, $E_{M M M}$ can at best consist only of those Belyi-extenders $γ (t)$ that map ${0, 1, \infty}$ onto ${0, 1, \infty}$ and such that their dessin is a tree.

Let me stop, for now, by asking for a reference (or counterexample) to perhaps the most startling claim in the Manin-Marcolli paper, namely that any 2-coloured tree can be realised as the dessin of a Belyi-extender!

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